Question

find the root of the quadratic equation y^2-7​

Answer 1

Answer:

Given

y

2

−7y+2=0

which is of the form ax

2

+bx+c=0

∴a=1,b=−7,c=2.

now, discriminant, D=b

2

−4ac

=(−7)

2

−4(1)(2)

= 49-8

= 41 > 0

Since D > 0, the two roots are real and distinct.