Question

The lionization potential of a hydrogen atom is 13.6v
what will be the acceleration of free fall on this orbit?
(a)-10.2 Ev (b) -3.40 Ev (c) +3.40 eV (d) -1.51 eV.​

Answer 1

Explanation:

Energy of electron in n

th

orbit of a hydrogen-like species

=

(n)

2

−13.6×(Z)

2

eV

Ionization potential =13.6Z

2

For H,Z =1

He

+

,Z =2.

∴ Ionization potential of He

+

=13.6×2

2

=54.4 eV