The lionization potential of a hydrogen atom is 13.6v
what will be the acceleration of free fall on this orbit?
(a)-10.2 Ev (b) -3.40 Ev (c) +3.40 eV (d) -1.51 eV.
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Explanation:
Energy of electron in n
th
orbit of a hydrogen-like species
=
(n)
2
−13.6×(Z)
2
eV
Ionization potential =13.6Z
2
For H,Z =1
He
+
,Z =2.
∴ Ionization potential of He
+
=13.6×2
2
=54.4 eV
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