Math, asked by choudharifarhan17, 1 year ago

find the root of the the following quadratic
equation x^2-3√5x+10=0​

Answers

Answered by shai3490lesh
1

Answer:

Step-by-step explanation:

x² - 2√5x -√5x +10

x(x-2√5) -√5(x-2√5)

(x-√5)(x-2√5)

∴ x = √5,2√5

Answered by priyanshu817
2

Step-by-step explanation:

hope it is helpful to you

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