Question

Find the root
$2x {}^{2} - 7x + 3$
of quadratic equation by completing square​

Answer 1

Answer:

Step-by-step explanation:

1. Make the x^2 coefficient 1, so divide the equation by 2.

Equation becomes--> x^2-7/2x+3/2=0

2. Take the x coefficient and divide by 2, then add and subtract it's square in the equation.

equation -->

x^2-7/2x+ 3/2 +(7/4)^2 - (7/4)^2 = 0

3.then complete the square -->

[x^2 - 7/2x + (7/4)^2] +3/2 - 49/16 = 0

(x- 7/4)^2 = -3/2 +49/16

(x- 7/4)^2 = 25/16

Taking square root both sides -->

(x- 7/4) = +- (5/4)

Required roots --> x = 12/4 =3

or,. x = 2/4 = 1/2