Question

find the roots :
1 . 2x² - 2√6x + 3 = 0
2x² - √6x - √6x + 3 = 0
√2x(√2x-√3 )-√3(√2x-√3)=0
(√2x-√3)(√2-√3)=0
if √2x-√3 = 0
√2x = √3
X = √3/√2
if √2x-√3 = 0
√2x = √3
x = √3/√2
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Answer 1

Answer:

2.44948974

Step-by-step explanation:

answer of root value

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