Question

Find the roots: 4√3 x2

+5x -2√3 = 0 ​

Answer 1

$\huge\underline\bold\red{SolutiON}$

$\sf 4\sqrt{3}\;x^2+5x-2\sqrt{3}=0$

$\sf 4\sqrt{3}\;x^2+8x-3x-2\sqrt{3}=0$

$\sf 4x(\sqrt{3}\;x+2)-\sqrt{3}\;(\sqrt{3}\;x+2)=0$

$\sf (4x-\sqrt{3}\;)\;(\sqrt{3}\;x+2)=0$

Either

x = √3/4

or

x= -2/√3