find the roots by completing the square 4x^2+4root3+3=0
anjali956h:
is it difficult to answer this ?
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4x^2+4√3x+3=0
or 4x^2+2√3x+2√3x+3=0
or 2x(2x+√3)+√3(2x+√3)=0
or (2x+√3)(2x+√3)=0
or (2x+√3)^2=
or 2x+√3=0
or 2x=-√3
.•. x= -√3/2 or -√3/2. answer
2nd method,
4x^2+4√3x+3=0
or (2x)^2+2×2x ×√3+(√3)^2=0
or (2x+√3)^2=0
after solving, x= -√3/2 or -√3/2 answer
or 4x^2+2√3x+2√3x+3=0
or 2x(2x+√3)+√3(2x+√3)=0
or (2x+√3)(2x+√3)=0
or (2x+√3)^2=
or 2x+√3=0
or 2x=-√3
.•. x= -√3/2 or -√3/2. answer
2nd method,
4x^2+4√3x+3=0
or (2x)^2+2×2x ×√3+(√3)^2=0
or (2x+√3)^2=0
after solving, x= -√3/2 or -√3/2 answer
thx
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