Question

the dimensions of a room are ( 10 m * 8 m * 3.3 m). how many men can be accommodated i this room if each man requires 3 m3 of space

Answer 1

The room is in shape of a cuboid. 
Given.
Length of cuboid= 10m
Breadth of cuboid= 8m
Height of cuboid= 3.3m
Volume of cuboid= l*b*h
                              = 10*8*3.3
                              = 264 m3
Given each man requires 3m3 of space
No of men can be accommodated in the room= Volume of room/ volume of each man
                                                                        = 264/3
                                                                        =88
Therefore, maximum 88 men can be accommodated in the room.

Answer 2

Answer:

volume of the room is equal to Tu

length x breadth X height

10m*8m*3•3m

264 metre cube

number of men can accommodated in room

264/3=88

no of men =88