Question

find the roots by completing the square method
i)3x²+ 11x+10=0
ii)2x² + x+4=0

Answer 1

$3 {x}^{2} + 11x + 10 = 0 \\ {x}^{2} + \frac{11x}{3} + \frac{10}{3} = 0 \\ {x}^{2} + \frac{11x}{3} = - \frac{10}{3} \\ {x}^{2} + \frac{11x}{3} + {( \frac{11}{6} )}^{2} = - \frac{10}{3} + {( \frac{11}{6} })^{2} \\ ( {x + \frac{11}{6} })^{2} = - \frac{ 10}{ 3} + \frac{121}{36} \\ ( {x + \frac{11}{6} })^{2} = \frac{ - 120 + 121}{36} \\ ( {x + \frac{11}{6}) }^{2} = \frac{1}{36} \\ x + \frac{11}{6} = \sqrt{ \frac{1}{36} } \\ x + \frac{11}{6} = \frac{1}{6} \\ x = \frac{1}{6} - \frac{11}{6} \\ x = - \frac{10}{6} \\ x = - \frac{ 5}{3}$
Hii... friend your answer