Question

Find the roots by factorisation: x^2-2√3x-9=0

Answer 1

$\textbf{Given:}$

$x^2-2\sqrt{3}x-9=0$

$\textbf{To find:}$

$\text{Roots of x^2-2\sqrt{3}x-9=0 }$

$\textbf{Solution:}$

$\text{Consider,}$

$x^2-2\sqrt{3}x-9=0$

$x^2-3\sqrt{3}x+\sqrt{3}x-9=0$

$x(x-3\sqrt{3})+\sqrt{3}(x-3\sqrt{3})=0$

$(x+\sqrt{3})(x-3\sqrt{3})=0$

$\implies\,x+\sqrt{3}=0\;\text{(or)}\;x-3\sqrt{3}=0$

$\implies\bf\,x=-\sqrt{3},\,3\sqrt{3}$

$\therefore\textbf{The roots are \bf-\sqrt{3} and \bf\,3\sqrt{3} }$

Find more:

Solve the following quadratic equations by factorization:(x+3/x-2)-(1-x/x)=17/4

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(2x-3)=root2x^2-2x+21

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Answer 2

Answer:

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