Question

find the roots by the method of perfect square (x+2) (x+3) -240 = 0​

Answer 1

Answer:

${x}^{2} + 3x + 2x + 6 - 240 = 0 \\ {x}^{2} + 5x - 234 = 0 \\ {x}^{2} + 18x - 13x - 234 = 0 \\ x(x + 18) - 13(x + 18) = 0 \\ (x - 13)(x+ 18) = 0 \\ x = 13 \: and \: x = - 18$

Answer 2

Step-by-step explanation:

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