find the roots for a quadratic equation 2x2+x-4 =0
Answers
Answered by
7
D=b^2-4ac
D=1+32
D=33
the roots are real and distinct
x=-b+-^D÷2a
x=-1+-^33÷4
x=-1+^33÷4 or x=-1-^33÷4
D=1+32
D=33
the roots are real and distinct
x=-b+-^D÷2a
x=-1+-^33÷4
x=-1+^33÷4 or x=-1-^33÷4
ketan72:
nice
Answered by
5
2x2+x-4 = 0
2x × 2 = 0 - x-4
2x × 2 = 0
2x = 0/2
2x = 0
x = 0/2
x = 0
b2 - 4ac formula use
2x × 2 = 0 - x-4
2x × 2 = 0
2x = 0/2
2x = 0
x = 0/2
x = 0
b2 - 4ac formula use
very good answer
Similar questions