Question

find the roots of 2x2-6x+4=0​

Answer 1

Answer:

$\huge\mathfrak\red{Hello}$

Step-by-step explanation:

$2x {}^{2} - 6x + 4 \\ \\ 2x {}^{2} - 4x - 2x + 4 \\ \\ 2x(x - 2) - 2(x - 2) \\ \\ (2x - 2)(x - 2) \\ \\ 2x = 2 \: and \: x = 2 \\ \\ \therefore \: x = 1 \: and \: 2$

Answer 2

Required Answer:-

Given:

• 2x² - 6x + 4 = 0

To find:

• The roots of the given equation.

Solution:

We have,

➡ 2x² - 6x + 4 = 0

Dividing both sides by 2, we get,

➡ x² - 3x + 2 = 0

Split the middle term,

➡ x² - x - 2x + 2 = 0

Factorise,

➡ x(x - 1) - 2(x - 1) = 0

➡ (x - 2)(x - 1) = 0

By zero product rule,

➡ Either (x - 2) = 0 or (x - 1) = 0

➡ x = 1, 2

★ Hence, the roots of the given quadratic equation are 1 and 2.

Answer:

• The roots of the given quadratic equation are 1 and 2.