If the lines 3x – 4y + 4 = 0 and 6x - 8y - 8 = 0 are tangents to the same circle, then the radius of the circle is
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3x- 4y+ 4=0 and 6x- 8y- 8=0
3x- 4y +4=0 -(6x-8y-8 =0)
3x- 4y+ 4=0- 6x+8y+8=0
-3x+ 4y+ 12 Answer
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