find the roots of
√3 x²+11x+6√3=0
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Answer:
√3x2 + 11x + 6√3 = 0
⇒ √3x2 + 9x + 2x + 6√3 = 0
⇒ √3x(x + 3√3) + 2(x + 3√3) = 0
⇒ (x + 3√3)(√3x + 2) = 0
x + 3√3 = 0
or √3x + 2 = 0
⇒ x = -3√3
Or x = - 2/√3 are two roots of the equation.
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