Math, asked by mahijaiswal167, 9 months ago

find the roots of
√3 x²+11x+6√3=0​

Answers

Answered by sandilya06
0

Answer:

√3x2 + 11x + 6√3 = 0

⇒ √3x2 + 9x + 2x + 6√3 = 0

⇒ √3x(x + 3√3) + 2(x + 3√3) = 0

⇒ (x + 3√3)(√3x + 2) = 0

x + 3√3 = 0

or √3x + 2 = 0

⇒ x = -3√3

Or x = - 2/√3 are two roots of the equation.

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