find the roots of 3a^2 -27a+13=0
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heya!!!
by using quadratic formulae
◆3a^2-27a+13=0 we have.
Discriminant 'd'=b^2-4ac
=)27^2-4*3*13
=). 729 -156
=)573
●but, roots of equation =-b+-√b^2-4ac/2a
=)27+-√573/6
=)162+√573/6 is 1st root of equation.◆
and ,162-√573/6 is 2nd root of equation ..◆
hope it help you.
@rajukumar☺
by using quadratic formulae
◆3a^2-27a+13=0 we have.
Discriminant 'd'=b^2-4ac
=)27^2-4*3*13
=). 729 -156
=)573
●but, roots of equation =-b+-√b^2-4ac/2a
=)27+-√573/6
=)162+√573/6 is 1st root of equation.◆
and ,162-√573/6 is 2nd root of equation ..◆
hope it help you.
@rajukumar☺
kakolookiyam:
how did 27 changed to 162?
but y do u need multiply by 6?
ok no problem
thnx done
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