Question

find the roots of √3x^2+10x-8√3=0

Answer 1

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Answer 2

Answer:

$x = -4\sqrt{3} \\\: Or\: x = \frac{2\sqrt{3}}{3}$ are two roots of given quadratic equation

Explanation:

Given quadratic equation:

√3x²+10x-8√3=0

Splitting the middle term, we get

=> √3x²+12x-2x-8√3=0

Rewriting the terms , we get

=> √3x²+(√3x)(4√3)-2x-2×(4√3)=0

=> √3x(x+4√3)-2(x+4√3)=0

=> (x+4√3)(√3x-2)=0

=> x+4√3=0 Or √3x-2 =0

$\implies x = -4\sqrt{3} \\\: Or \:x = \frac{2}{\sqrt{3}}$

$\implies x = -4\sqrt{3} \\\: Or \:x = \frac{2\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}$

$\implies x = -4\sqrt{3} \\\: Or\: x = \frac{2\sqrt{3}}{3}$

Therefore,

$x = -4\sqrt{3} \\\: Or\: x = \frac{2\sqrt{3}}{3}$ are roots of given quadratic equation.

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