Question

Find the roots of √3x2-2x-√3=0

Answer 1

√3 x² - 2x - √3 = 0
√3 x² - 3x + x - √3 = 0
√3 x(x - √3) + 1(x - √3) = 0
(x - √3 ) (√3 x + 1) = 0
x - √3 = 0 , √3 x +1 = 0
x = √3 , x = -1/√3

Answer 2

Given: $\sqrt{3}x^2-2x-\sqrt3=0$

Using factorization,

$\sqrt{3}x^2-3x+x-\sqrt3=0\\\sqrt{3}x(x-\sqrt{3})+1(x-\sqrt3)=0\\(x-\sqrt{3})(x+1)=0$

$(x-\sqrt{3})=0\\x=\sqrt{3}$

or

$x+1=0\\x=-1$

The roots of the given equation are $\sqrt3$ and $-1$.