find the roots of 3xsquare+11x+10 by completing square method
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Step-by-step explanation:
3xsquare+11x+10
x2+11x/3+10
x2+11x+121/36-121/36 +10
(x+11/3)2-(121/36-10)
(x+11/3)2 -(139/36)
(x+11/3)2 -( root139/6)2
(x+11/3-root139/6) (x+11/3+root139/6)
[X + (22 - root 139 )upon 6 ] [X + (22 + root 139) upon 6 ]
[X + (22 - root 139) upon 6] =0
x= -(22-root139)/6
and x= -(22+root139) /6
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