Question

• find
the roots of a quadratic equation
2x² +3x-5-0​

Answer 1

Equation: 2x² + 3x - 5 = 0

=> 2x² + 3x - 5 = 0

=> 2x² - 2x + 5x - 5 = 0

=> 2x ( x - 1 ) + 5 ( x - 1 ) = 0

=> ( 2x + 5 )( x - 1 )

Zeroes are 1 and -5/2

Answer 2

Answer:

-5/2 & 1

Step-by-step explanation:

2x²+3x-5=0

find two numbers whose sum is 3 and product-5×2=-10

these are 5,-2

2x²-2x+5x-5=0

2x(x-1)+5(x-1)=0

factors:2x+5 & x-1

2x+5=0&x-1=0

solving both simple linear equations

x=-5/2&1