Question

Find the roots of equation a^2 x^2 - 3ab + 2b^2 =0 using completing square

Answer 1

Hii there!!

a² x² -3abx + 2b² = 0
=)a² x² - abx - 2abx + 2b² = 0
=)ax( ax - b ) - 2b( ax - b ) = 0
=) ( ax - b )( ax -2b ) = 0

So, ( ax -b ) = 0 or ax -2b = 0
ax = b or ax = 2b

=) x = b / a or x = 2b / a

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Answer 2

Answer:

a^2 - 3abx + 2b^2

Step-by-step explanation:

a² x² -3abx + 2b² = 0  <---------------yOUR qUESTION

a² x² - abx - 2abx + 2b² = 0  <---------------splitting middle

ax( ax - b ) - 2b( ax - b ) = 0 <--------------Taking common

( ax - b )( ax -2b ) = 0 <-------------------grouping [yeah,you know the basic stuff]

Therefore ,

( ax -b ) = 0 or ax -2b = 0  <-----------------taking aside all other elements then x

ax = b or ax = 2b  

x = b / a or x = 2b / a  <-----------------there you go :)