Find the roots of following quadratic equations, if they exist by the method of completing square: 2(x)2-5x-12=0
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Hi friend here is your answer :-
2x^2 - 5x - 12=02x^2 - 8x + 3x -12 = 02x(x-4) + 3(x-4)=0
Therefore x = -3/2 or x=4As u r finding the exiting square in the roots,x=4 is the answer as it is 2 square
Hope the answer helped u :)
2x^2 - 5x - 12=02x^2 - 8x + 3x -12 = 02x(x-4) + 3(x-4)=0
Therefore x = -3/2 or x=4As u r finding the exiting square in the roots,x=4 is the answer as it is 2 square
Hope the answer helped u :)
vaibhavc1:
Pls do mark as brainliest answer ;)
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