Find the roots of quadratic equation
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x^2 + 5 x + 6
X square + 6 x minus x + 6
X(X+6)+1(X+6)
(X+1)(X+6)
zeros are minus 1 and minus 6
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60
Answer:
x² + 5x + 6 = 0
=> x² + 2x + 3x + 6 = 0
=> x( x + 2) + 3( x + 2) = 0
=> ( x + 2)( x + 3 ) = 0
=> x + 2 = 0 or x + 3 = 0
=> x = - 2 or x = - 3
so the roots are - 2, - 3
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