Question

find the roots of quadratic equation​

Answer 1

Step-by-step explanation:

It doesn't have any real roots !!

D < 0

Answer 2

Step-by-step explanation:

y2-2y-35=0

Two solutions were found :

y = 7

y = -5

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring y2-2y-35

The first term is, y2 its coefficient is 1 .

The middle term is, -2y its coefficient is -2 .

The last term, "the constant", is -35

Step-1 : Multiply the coefficient of the first term by the constant 1 • -35 = -35

Step-2 : Find two factors of -35 whose sum equals the coefficient of the middle term, which is -2 .

-35 + 1 = -34

-7 + 5 = -2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and 5

y2 - 7y + 5y - 35

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-7)

Add up the last 2 terms, pulling out common factors :

5 • (y-7)

Step-5 : Add up the four terms of step 4 :

(y+5) • (y-7)

Which is the desired factorization