Question

find the roots of quadratic equation​

Answer 1

Answer:

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Answer 2

In the equation : 2x²-6x+9/2= 0

a= 2

b= -6

c= 9/2

Using Quadratic Formula :-

$x = - b + - \sqrt{} {b}^{2} - 4ac \div 2a$

x = -(-6)+-√(-6)²-4(2)(9/2) / 2(2)

= 6+-√36-4(9) / 4

= 6+-√36-36 / 4

= 6+-√0 / 4

= 6+-0 / 4

Now , there are two cases for 6+-0 / 4

Case - 1

= 6+0 / 4

= 6/4 OR 1.5

Case - 2

= 6-0 / 4

= 6/4 OR 1.5

Now the roots are 6/4 and 6/4 OR 1.5 and 1.5

Roots are real and equal

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