Math, asked by supridadsprincess, 9 months ago

find the roots of quadratic equation 3 X square + 11 x + 10 is equal to zero completing square method

Answers

Answered by hkthakur302

6

Here's How we do that .✌️

Attachments:

Answered by brainlyaryan12

3

$<body bgcolor="r"><font color =pink>$

$\huge{\orange{\fbox{\fbox{\blue{\bigstar{\mathfrak{\red{Answer}}}}}}}}$

$<marquee scrollamount = 700>✌️✌️✌️</marquee>$ $<marquee scrollamount = 500>⭐⭐⭐</marquee>$

=>> 3x²+11x+10=0

=>> 3x²+11x = -10

On dividing whole equation by 3

=>> x²+ $\frac{11}{3}$ = $\frac{-10}{3}$

=>> x²+ $\frac{11}{3}$ + $\frac{11}{6}^2$ = $\frac{-10}{3}$ + $\frac{121}{36}$

=>> $(x+{\frac{11}{6})^2}$ = $\frac{121-120}{36}$

=>> $(x+{\frac{11}{6})^2}$ = $\frac{1}{36}$

=>> x+ $\frac{11}{6}$ = $\sqrt{\frac{1}{36}}$

=>> x+ $\frac{11}{6}$ = ± $\frac{1}{6}$

First Solution:

=>> x = $\frac{1}{6}$ - $\frac{11}{6}$

=>> x = $\frac{-10}{6}$

=>> x = $\frac{-5}{3}$

Second solution:

=>> x = $\frac{-1}{6}$ - $\frac{11}{6}$

=>> x = $\frac{-12}{6}$

=>> x = -2

$\huge\orange{\fbox{\pink{x={\frac{-5}{3}}}}}$

$\huge\orange{\fbox{\pink{\text{x=-2}}}}$

$\huge{\purple{\bigstar{\blue{\text{Hope it helps...}}}}}$

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