Question

Find the roots of quadratic equation √3x^2-2x-√3

Answer 1

Þ √3 x^2 - 2x - √3 = 0
Þ  √3 x^2 - 3x + x - √3 = 0
Þ √3x (x-√3) + (x√3) = 0
Þ (x-√3)(√3x+1) = 0
Þ x = √3  or x = -1/√3 i.e. -√3/3

Answer 2

root of 3 x^2- 2x -root of 3
=root of 3 x^2-3x+x-root of 3
=root of 3 x(x-root of 3)+1(x-root of 3)
=(root of3 x+1)(x-root of 3)
if it help you , please mark as brainlist
$( \sqrt{3} x + 1)(x - \sqrt{3)}$