find the roots of quadratic equation √3x²-2x²-√3=0
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Given 3x2 – 2√2 x – 2√3 = 0 Using the quadratic formula to find the roots of quadratic equation are - b ± b 2 - 4 a c 2 a , where b2 - 4ac is called the discriminant of the quadratic equation. Here a = 3 , b = -2√2 and c = – 2√3 b2 - 4ac = 8 + 24√3 x = [ 2√2 ± √(8 + 24√3) ] / 6. x = [ 2(√2 ± √(2 + 6√3) )] / 6. ∴ x = [ (√2 ± √(2 + 6√3) )] / 3.
Priyanshu31072002:
You are wrong formula is correct but value of a=√3
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Answer:
√3x²-2x²-√3=0
√3x²-3x+x-√3=0
√3x(x-√3)+1(x-√3)=0
(√3x+1)(x-√3)=0
Now here
X=-1/√3
X=√3
Step-by-step explanation:
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