Question

find the roots of quadratic equation of x²=4​

Answer 1

Answer:

x^2= 4

x= 2

root of equation is 2.

Answer 2

Answer:x²=4​

x²-4​=0

when compared to ax²+bx+c=0

a=1, b=0,c=-4

b²-4ac= (0)²-4​(1 X -4)

          = 0 -4(-4)

          =-4 X-4

          = 16

x = $\frac{-b\sqrt{b^{2}-4ac} }{2a}$

x= $\frac{\sqrt{16} }{1}$

x = ±4

∴x=4 ∴x-4

∴The roots of the given quadratic equation are +4 and -4