Question

find the roots of quadratic equation root 2 X square + 7 x + 5 root 2 is equals to zero

Answer 1

Hope this helps you....✌

Answer 2

$0 = \sqrt{2} x {}^{2} + 7x + 5 \sqrt{2} \\ = \sqrt{2} x ^{2} + 2x + 5x + 5 \sqrt{2} \\ = \sqrt{2}x (x + \sqrt{2} ) + 5(x + \sqrt{2} ) \\ = ( \sqrt{2} x + 5)(x + \sqrt{2} )$
root2 x + 5 = 0 or x+root2 = 0
x = -5/root2 or x = -root2

If we rationalize, then it would be -5×root 2/2. for first answer, otherwise.

mark as brainliest,if it helped.