Question

find the roots of quadratic equation X square + 4 x minus 5 equal zero completing the square method​

Answer 1

Answer:

Step-by-step explanation:

x² +4x-5

=(x)²+2×x²+(2)²-(2)²-5=0

(x+2)²-4-5=0

(x+2)²=9

x+2=+ or-$\sqrt{9}$

x=+ or -3-2

x= -3-2  ,  3-2

x=-5        ,x=1

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Answer 2

The roots of the quadratic equation are 1 or -5.

Step-by-step explanation:

Given : Quadratic equation $x^2+4x-5=0$

To find : find the roots of quadratic equation by completing the square method​ ?

Solution :

Quadratic equation $x^2+4x-5=0$

We have to add and subtract the square of half of the coefficient of x,

i.e. $\frac{4}{2}=2$

So,  $x^2+4x-5+(2)^2-(2^2)=0$

Applying identity, $(a+b)^2=a^2+b^2+2ab$

$(x+2)^2-4-5=0$

$(x+2)^2=9$

Taking root both side,

$x+2=\pm 3$

 $x+2=3$  or  $x+2=-3$

 $x=1$  or  $x=-5$

Therefore, the roots of the quadratic equation are 1 or -5.

#Learn more

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