Question

Find the roots of quadratic equation x2-3√5x+10=0

Answer 1

Solution:

Given quadratic equation:

x²-3√5x+10=0

Splitting the middle term, we

get

=> x²-2√5x-√5x+10=0

=> x²-2√5x-√5x+2×5=0

=> x²-2√5x+√5x +2×√5×√5=0

=> x(x-2√5)-√5(x-2√5)=0

=> (x-2√5)(x-√5)=0

=> x-2√5 =0 Or x-√5 = 0

=> x = 2√5 Or x = √5

Therefore,

Roots of given Quadratic equation are:

2√5 Or √5

•••••

Answer 2

Answer:

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Step-by-step explanation:

by splitting the middle term

Hence, the roots of the given equation are2√5 and √5