find the roots of quardratic equation 2xsquare-2root2x+1=0 in factorization method
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2x square - 2√2x+1=0
2x2 -√2x -√2x +1=0
√2x(√2x-1)-1(√2x-1)=0
(√2x-1)(√2x-1)=0
√2x-1=0 Or √2x-1=0
√2x=1. √2x=1
x=1/√2. x=1/√2
2x2 -√2x -√2x +1=0
√2x(√2x-1)-1(√2x-1)=0
(√2x-1)(√2x-1)=0
√2x-1=0 Or √2x-1=0
√2x=1. √2x=1
x=1/√2. x=1/√2
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