Math, asked by srujansoma2005, 10 months ago

Find the roots of the eqn: 3x²- 3✓2x+1

Answers

Answered by pranav20043105
0

Step-by-step explanation:

3x^2 - 3√2x+1

b^2 - 4ac

(- 3√2)^2 - 4(3)(1)

9(2) - 12

6

x= -b+-√b^-4ac ÷ 2a

x= 3√2 +- √6 ÷ 2

there are two values of X

x=3√2+√6÷2

x=3√2-√6÷2

hope it helps

Similar questions