Find the roots of the eqn: 3x²- 3✓2x+1
Answers
Answered by
0
Step-by-step explanation:
3x^2 - 3√2x+1
b^2 - 4ac
(- 3√2)^2 - 4(3)(1)
9(2) - 12
6
x= -b+-√b^-4ac ÷ 2a
x= 3√2 +- √6 ÷ 2
there are two values of X
x=3√2+√6÷2
x=3√2-√6÷2
hope it helps
Similar questions