Question

Find the roots of the equation 5x2-6x-2=0 by using quadratic formula

Answer 1

Answer:

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$5 {x}^{2} - 6x - 2 = 0$

$x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

here a=5,b=-6,c=-2

$x = \frac{ - ( - 6) ± \sqrt{ {( - 6) - 4 \times 5 \times - 2}^{2} } }{2 \times ( - 2)}$

$x = \frac{6 ± \sqrt{36 + 40} }{ - 4}$

$x = - \frac{3 ± \sqrt{76} }{ 2}$

$x = - \frac{3 ±2 \sqrt{19} }{2}$

Here is your answer

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Answer 2

$\huge\underline\bold\red{Answer}$

Given :-

• A quadratic polynomial 5x² - 6x - 2 = 0

To Find :-

• Roots of the quadratic polynomial.

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Comparing 5x² - 6x - 2 = 0 with ax² + bx +c = 0 ,

• a = 5

• b = - 6

• c = - 2

Let's calculate delta

∆ = b² - 4ac

=> ∆ = (- 6)² - { 4 (5) (- 2) }

=> ∆ = 36 + 40

=> ∆ = 76

Value of x is calculated by -

x = ( - b ± √∆ ) / 2a

=> x = (6 - √76) / (2 × 5)

=> x = (6 ± 2√19) / 10

=> x = (3 ± √19) / 5

Hence, value of x can be (3 - √19) / 5 or (3 + √19) / 5.

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