Question

Find the roots of the equation a2x2 - 3abx + 2b2 = 0 by method of completing the square.

Answer 1

Hi ,

a²x² - 3abx + 2b² = 0

a²x² - 3abx = - 2b²

divide each term with a² both sides of the

equation ,

x² - 3bx/a = - 2b²/a²

x² - 2 × x × (3b/2a)+(3b/2a)² = ( 3b/2a )² - 2b²/a²

( x - 3b/2a )² = 9b²/4a² - 2b² /a²

= ( 9b² - 4b² ) /a²

= 5b²/a²

x - 3b/2a = ± √ ( 5b²/a² )

x = 3b/2a ± √5 ( b/a )

= [ 3b ± 2√5 b ] / 2a

= ( 3 ± 2√5 )b/ 2a

I hope this helps you.

:)

Answer 2

Step-by-step explanation:

I hope u get it. If yes then don't forget me to follow.Also mark my answer as brainlist answer...