Question

Find the roots of the equation using quadratic formula 9x2 -15x+6=0

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$2 \: or \: \frac{2}{3}$

Step-by-step explanation:

$9 {x}^{2} - 15x + 6 = 0$

CHECKING IF ROOT ARE REAL

$a = 9 \: \: \: \: \: \: \: b = - 15 \: \: \: \: \: \: \: c = 6 \\ d = {b}^{2} - 4ac \\ \: \: \: = {( - 15)}^{2} - (4)(9)(6) \\ \: \: \: = 225 - 216 \\ \: \: \: =9$

Therefore, the roots are real

So,

Using quadratic formula,

$\frac{ - b + - \sqrt{d} }{2a} \\ = \frac{( - 15) + - \sqrt{9} }{2 \times 9} \\ = \frac{15 + - 3}{18} \\ = \frac{15 + 3}{18} \: or \: \frac{15 - 3}{18} \\ = \frac{18}{18} \: or \: \frac{12}{18} \\ = 1 \: or \: \frac{2}{3}$

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