Question

Find the roots of the equation x^2-4x+3 + x^2-9 = 4x^2-14x+6

Answer 1

Step-by-step explanation:

there are two equations

lhs=rhs

if we take all together..

3x^2-10x+3-x^2+9=0

2x^2-10x+12=0..... divide by 2 both sides

..

x^2-5x+6=0

x^2-3x-2x+6=0

(x-3)(x-2)=0

x=3 or 2