Find the roots of the equation (x2 + 3x)2 – (x² + 3x) –6=0.
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Solve : (x2 + 3x)2 – (x2 + 3x) – 6 = 0
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asked Feb 16, 2019 in Class X Maths by navnit40 (-4,945 points)
Solve : (x2 + 3x)2 – (x2 + 3x) – 6 = 0
quadratic equation
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answered Feb 16, 2019 by priya12 (-12,637 points)
Given equation is (x2 + 3x)2 – (x2 + 3x) – 6 = 0
Putting x2 + 3x = y , the given equation becomes
y2 – y – 6 = 0
⇒ y2 – 3y + 2y – 6 = 0
⇒ y(y – 3) + 2(y – 3) = 0
⇒ (y – 3)(y + 2) = 0
⇒ y – 3 = 0 or y + 2 = 0
⇒ y = 3 or y = - 2
- But x2 + 3x = y
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