Question

find the roots of the equation x²-3x-m{ m + 3} = 0,where m is an constant .

Answer 1

hope it should be right!

Answer 2

We find
x2 - 3x - m (m+3) = 0
=> x2 - 3x - m2 - 3m = 0
=> x2 - m2 - 3x - 3m = 0
=> (x+m)(x-m) - 3 (x-m) = 0
=> (x - m) (x + m - 3) = 0

So, the roots are
x = m, - m + 3.