find the roots of the equation x²-3x-m{ m + 3} = 0,where m is an constant .
Swarup1998:
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hope it should be right!
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we hv to find the roots u hv done it half only.........
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We find
x2 - 3x - m (m+3) = 0
=> x2 - 3x - m2 - 3m = 0
=> x2 - m2 - 3x - 3m = 0
=> (x+m)(x-m) - 3 (x-m) = 0
=> (x - m) (x + m - 3) = 0
So, the roots are
x = m, - m + 3.
x2 - 3x - m (m+3) = 0
=> x2 - 3x - m2 - 3m = 0
=> x2 - m2 - 3x - 3m = 0
=> (x+m)(x-m) - 3 (x-m) = 0
=> (x - m) (x + m - 3) = 0
So, the roots are
x = m, - m + 3.
thanks for giving me full answer
No problem. Hope it helps you.
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