Find the roots of the following equation by method of factorisation : 2x^2-x+1/8=0
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Find the roots of the following equation by method of factorisation : 2x^2-x+1/8=0
Step-by-step explanation:
2x ^ 2 - x + 1/8
= 1 8 (16x^ 2 -8x+1)
= 1 8 (16x^ 2 -4x-4x+1)
1 8 = (4x(4x -1)-1(4x-1))
= 1 8 (4x-1)^ 2
Roots of this equation are the values for which (4x - 1) ^ 2 = 0
Rightarrow x=1/4 or x = 1/4
therefore(4x-1)=0 or (4x - 1) = 0
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