Find the roots
of the following
following equation
x-1/x-2+x-3/x-4 =3×1/3, ( x dosenot = 2, 4
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Step-by-step explanation:
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Step-by-step explanation:
(x-1) / (x-2) +(x-3) / (x-4) = 1
=> (x-1)(x-4) + (x-3)(x-2) = (x-4)(x-2)
=> x²-5x+4+x²-5x+6 =x²-6x+8
=> x²-4x+2=0
x= 2±√(16-8)/2
= 2±2√2/2
= 2±√2
root of eqn , alfa= 2+√2 and beta= 2-√2
Here used quadratic formula
x= [-b/±√(b²-4ac)]/2a
= -b/2a ± √(b²-4ac)/2a
hope this helps you
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