Question

find the roots of the following quadratic equation by factorization : 2x^2+x-6=0​

Answer 1

Answer:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 1 + - \sqrt{ {( - 1)}^{2} - 4.2.( - 6)} }{2.2} \\ = \frac{ - 1 + - \sqrt{1 + 48} }{4} \\ = \frac{ - 1 + - \sqrt{49} }{4} \\ = \frac{ - 1 + - (7)}{4} \\ here \: x \: will \: have \: two \: values \\ x = \frac{ - 1 + 7}{4} = \frac{6}{4} = \frac{3}{2} \\ x = \frac{ - 1 - 7}{4} = \frac{ - 8}{4} = - 2$

Hope this helps mate...