Question

Find the roots of the following quadratic equation by using the method of factorisation: 6xsq.-13x-5=0.​

Answer 1

Step-by-step explanation:

$6x {}^{2} - 15x + 2x - 5 = 0 \\ \\ \\ 3x(2x - 5) + 1(2x - 5) = 0 \\ \\ \\ \\ (3x + 1)(2x - 5) = 0 \\ \\ \\ \\ \\ 3x + 1 = 0 \\ \\ \\ \\ x = \frac{ - 1}{3} \: \: \: or \: \: 2x - 5 = 0 \\ \\ \\ \\ x = \frac{5}{2}$

Answer 2

Step-by-step explanation:

pls check the question properly.

6x^2-13x+5=0

the above step.

6x^2-10x-3x+5=0

2x(3x-5)-1(3x-5)=0.

(2x-1)(3x-5)=0.

so 2x-1=0

x=1/2

3x-5=0

x=5/3.