Question

find the roots of the following quadratic equation : $2x^{2} +2\sqrt 2+1=0$

Answer 1

➡ 2x² + 2√2x + 1 = 0

➡ 2x² + √2x + √2x + 1 = 0

➡ √2x ( √2x + 1 ) + 1 ( √2x-+ 1 ) = 0

➡ (√2x + 1) (√2x ( 1) =0

➡ √2x + 1 = 0 ; √2x + 1 = 0

➡ √2x = 0 - 1 ; √2x = 0 - 1

➡ √2x = -1 ; √2x = -1

➡ x = -1/√2 ; x = -1/√2

∴ Roots are -1/√2 & -1/√2

Step-by-step explanation:

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