Question

find the roots of the following quadratic equations by the factorization method 2 X square + 5 by 3 x minus 2 equals zero

Answer 1

$(2 {x}^{2} + 5) \div (3x - 2) = 0 \\ \frac{2x^{2} + 5}{3x - 2} = 0 \\ \\ 2 {x}^{2} + 5 = 3x - 2 \\ 2 {x}^{2} - 3x = - 2 - 5 \\ x(2x - 3) = - 7.. \\ \\ i \: hope \: your \: question \: is \: wrong. \\ plz \: check \: and \: post \: again \:$
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