Question

Find the roots of the following quadratic equations :(I)X^2-4X-5=0 (II)2X^2+2√2 X +1 =0​

Answer 1

Answer:

(1) 5,-1

(2)  $-\sqrt{2}$/2 , $- \sqrt{2}$/2

Step-by-step explanation:

formula for the equationof the form $ax^2+bx+c=0$ is

$(-b+\sqrt{b^2-4ac} )/2a$,

$(-b-\sqrt{b^2-4ac} /2a$

substituting values of a,b,c in the formula you get the answer