Question

Find the roots of the given quadratic equation x2-4x+1=0

Answer 1

Answer:

The roots of the quadratic equation is (0.268, 3.732).

Step-by-step explanation:

The quadratic equation is: $x^{2}-4x+1=0$

The roots of a quadratic equation are: $x=\frac{-b\pm\sqrt{b^{2}-4ac} }{2a}$

The value of a = 1, b = -4 and c = 1.

The roots are:

$x=\frac{-(-4)\pm\sqrt{(-4)^{2}-(4\times1\times1)} }{2\times1}\\=\frac{4\pm\sqrt{12} }{2}\\ =\frac{4\pm2\sqrt{3} }{2} \\=2\pm\sqrt{3} \\=(0.268,3.732)$

Thus, the roots of the quadratic equation is (0.268, 3.732).

Answer 2

Answer:

Step-by-step explanation:

x^2-4x+1 = 0

x = (4±√(16-4×1×1))/2×1

= 2±√3

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