Find the roots of the quadratic equation 2√3xsquare_5x+√3
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the solution is of 2√3x²-5x+√3 is
=2√3x²+(-6+1) x+√3
=2√3x²-6x+x+√3
=2√3x (x-√3) -1 (x-√3)
=(2√3x-1) (x-√3)
therefore the roots are
x = 2√3x-1 = 0
x = 2√3x = 1
x = 1/2√3 = 2√3/12
x = x-√3 = 0
x = √3
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=2√3x²+(-6+1) x+√3
=2√3x²-6x+x+√3
=2√3x (x-√3) -1 (x-√3)
=(2√3x-1) (x-√3)
therefore the roots are
x = 2√3x-1 = 0
x = 2√3x = 1
x = 1/2√3 = 2√3/12
x = x-√3 = 0
x = √3
PLEASE MARK ME AS BRAINLIEST
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