find the roots of the quadratic equation 2x^2 +5/3x-2=0 by factorisation
...........please give me ans fast
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Answered by
60
6x^2+5x-6=0
(3x-2) (2x+3) =0
x = (2/3, -3/2)
(3x-2) (2x+3) =0
x = (2/3, -3/2)
Answered by
141
Hey
Multiply the whole equation by 3
we get 6x² +5x - 6 = 0
6x² +9x - 4x -6 =0
3x(2x + 3) - 2(2x + 3) = 0
(3x-2)=0 or (2x+3)=0
x = 2/3 or x = -3/2
Hope it helps
Pls mark me brainliest :)
Multiply the whole equation by 3
we get 6x² +5x - 6 = 0
6x² +9x - 4x -6 =0
3x(2x + 3) - 2(2x + 3) = 0
(3x-2)=0 or (2x+3)=0
x = 2/3 or x = -3/2
Hope it helps
Pls mark me brainliest :)
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